1) According to the maximum working temperature of 1350°C, take the surface load of the component as shown in Figure 12-1! = 10W/cm2,

2) Calculate the total efficiency of the components and the product Sa = 1400 (cm2) more than

3) According to the table] 2-40, the size of the silicon carbide rod is 18/250/350; at this time, it can be found that the silicon carbide rod s = 14K4cm/root,

R=1.3Q)

4) The number of silicon carbon rods n=1400/141.2=9.9. Since it is a three-phase power supply, the number of roots should be a multiple of 3, and

141.4

The rubbish is even numbered, so take 12 and twist 6. Every 2 strings are a group of I

5) The distance A = Y^ = 74.5Cmm) between each two of the inspection grates, more than 2 </( = 36oim) qualified"

T+1

6) The resistance of each phase of the element = = 2 xi.3 = 2.6 (£2) (the two groups are connected in series to form DDh

7) The secondary voltage of the transformer at full load £ 2.6X2.3X 10* =78 (V). Power per phase iV=^ =

6

2.3(kW)»

70

8) Phase current

9) Line current? 58 52(A),

10) Electricity [in the adjustment range = (0.35~2.0>x78 = 27.3~156( V ) ) according to the maximum working temperature of 1350°C according to Figure 12-1! Take the surface load of the component = 10W/cm2,

2) Calculate the total efficiency of the components and the product Sa = 1400 (cm2) more than

3) According to the table] 2-40, the size of the silicon carbide rod is 18/250/350; at this time, it can be found that the silicon carbide rod s = 14K4cm/root,

R=1.3Q)

4) The number of silicon carbon rods n=1400/141.2=9.9. Since it is a three-phase power supply, the number of roots should be a multiple of 3, and

141.4

The rubbish is even numbered, so take 12 and twist 6. Every 2 strings are a group of I

5) The distance A = Y^ = 74.5Cmm) between each two of the inspection grates, more than 2 </( = 36oim) qualified"

T+1

6) The resistance of each phase of the element = = 2 xi.3 = 2.6 (£2) (the two groups are connected in series to form DDh

7) The secondary voltage of the transformer at full load £ 2.6X2.3X 10* =78 (V). Power per phase iV=^ =

6

2.3(kW)»

70

8) Phase current

9) Line current? 58 52(A),

10) Electricity [in the adjustment range = (0.35~2.0>x78 = 27.3~156( V )